document.write( "Question 433981: 10 gallons of a 15.0% alcohol solution are to be mixed with a 28.0% alcohol solution to make a 20.0% alcohol solution. How many gallons of a 28.0% alcohol must be used? How many gallons of a 20.0% alcohol solution are made? \n" ); document.write( "

Algebra.Com's Answer #853273 by greenestamps(13258) $\"\"$ $\"About$

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\n" ); document.write( "The ratio in which the two alcohol solutions must be mixed is exactly determined by where the 20% of the mixture lies between the 15% and 28% of the two ingredients.

\n" ); document.write( "The difference between 15 and 20 is 5; the difference between 20 and 28 is 8.

\n" ); document.write( "So the two ingredients must be mixed in the ratio 5:8. Note that since 20% is closer to 15% than it is to 28%, the larger portion must be the 15% alcohol solution.

\n" ); document.write( "Solve the problem using a proportion, given that we are using 10 gallons of the 15% alcohol.

\n" ); document.write( " $\"5%3A8=x%3A10\"$
\n" ); document.write( " $\"8x=50\"$
\n" ); document.write( " $\"x=50%2F8=6.25\"$

\n" ); document.write( "ANSWERS:
\n" ); document.write( "(1) 6.25 gallons of the 28% alcohol should be used
\n" ); document.write( "(2) the mixture will be 10+6.25 = 16.25 gallons

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