document.write( "Question 434074: The sum of the present ages of john and his father is 89 years. After 11 years the age of father will be twice the age of john at that time, find their present ages. \n" ); document.write( "

Algebra.Com's Answer #853269 by josgarithmetic(39702) $\"\"$ $\"About$

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document.write( "               NOW           IN 11 YEARS\r\n" );
document.write( "John           89-m          89-m+11=100-m\r\n" );
document.write( "Father          m             m+11\r\n" );
document.write( "SUM             89           89+2*11=111                 \r\n" );
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\n" ); document.write( "Description makes that $\"m%2B11=2%28100-m%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"m%2B11=200-2m\"$
\n" ); document.write( " $\"3m=200-11\"$
\n" ); document.write( " $\"3m=189\"$
\n" ); document.write( " $\"highlight%28m=63%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "John's Father, 63
\n" ); document.write( "John, 26 \n" ); document.write( "

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