document.write( "Question 434946: Bertha has 33 coins in her pocket totaling $5.25. If she only has nickles and quarters, how many of each type of coin does she have \n" ); document.write( "

Algebra.Com's Answer #853264 by ikleyn(53538) $\"\"$ $\"About$

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\n" ); document.write( "Bertha has 33 coins in her pocket totaling $5.25. If she only has nickles and quarters,
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\n" ); document.write( "\n" ); document.write( "        In the post by @mananth, his second equation in the 4th line is written incorrectly.\r
\n" ); document.write( "\n" ); document.write( "        It makes all the subsequent solution defective.\r
\n" ); document.write( "\n" ); document.write( "        So, I came to make the job accurately, in a way as it SHOULD be done.\r
\n" ); document.write( "\n" ); document.write( "        In my solution, I will use one unknown and one equation, since it provides a shorter way.\r
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document.write( "Let x be the number of quarters.\r\n" );
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document.write( "Then the number of nickels is (33-x).\r\n" );
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document.write( "Write the total value equation\r\n" );
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document.write( "    25x + 5*(33-x) = 525  cents.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    25x + 165 - 5x = 525,\r\n" );
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document.write( "    25x - 5x = 525 - 165,\r\n" );
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document.write( "       20x   =    360,\r\n" );
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document.write( "         x   =    360/20 = 18.\r\n" );
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document.write( "ANSWER.  18 quarters and 33-18 = 15 nickels.\r\n" );
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document.write( "CHECK  for the total  25*18 + 5*15 = 525 cents,  precisely as it is given in the problem.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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