document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428471>Question 428471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to use substitution method<BR>\n" );
document.write( "15x-10y=1<BR>\n" );
document.write( "5y=-2+15x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853245 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13258)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Pay close attention to the solution from tutor @ikleyn.<br><BR>\n" );
document.write( "In a typical algebra class, given a system of two linear equations, you are taught to solve one of the equations for one of the variables (by itself) and substitute the result in the other equation.<br><BR>\n" );
document.write( "But as the tutor shows in this problem, the solution is much easier because the expression \"15x\" appears in both of the given equations; so solving one of the equations for \"15x\" and substituting in the other equation makes the solution easy.<br><BR>\n" );
document.write( " </SPAN>\n" );
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