document.write( "Question 419077: Dave Horn invested half of his money at 5%, one-tird of his money at4%, and the rest at 3.5%. If his total annual investment incomw is $530, how much had he invested? \n" ); document.write( "
Algebra.Com's Answer #853234 by josgarithmetic(39702)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "RATE%              INVEST              INCOME\r\n" );
document.write( "   5                 p/2                0.05(p/2)\r\n" );
document.write( "   4                 p/3                0.04(p/3)\r\n" );
document.write( "   3.5             p-p/2-p/3=p/6        0.035(p/6)\r\n" );
document.write( "TOTAL                                    530 \r\n" );
document.write( "

\n" ); document.write( "\"%280.05%2F2%2B0.04%2F3%2B0.035%29p=530\"\r
\n" ); document.write( "\n" ); document.write( "l.c.d. is 12\r
\n" ); document.write( "\n" ); document.write( "\"12p%280.05%2F2%2B0.04%2F3%2B0.035%2F6%29=530%2A12\"\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"%280.3%2B0.16%2B0.07%29p=6360\"\r
\n" ); document.write( "\n" ); document.write( "\"0.53p=6360\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p=12000%29\" the original amount invested among the three accounts.\r
\n" ); document.write( "\n" ); document.write( "6000 at 5%
\n" ); document.write( "4000 at 4%
\n" ); document.write( "2000 at 3.5% \n" ); document.write( "
\n" );