document.write( "Question 423336: A liter of orange fruit drink contains 22% orange juice. How many millimeters of orange juice must be added to produce a mixture containing 50% orange juice? \n" ); document.write( "
Algebra.Com's Answer #853213 by greenestamps(13272)\"\" \"About 
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\n" ); document.write( "Any 2-part mixture problem like this can be solved using the following non-algebraic method.

\n" ); document.write( "We are mixing 22% juice with 100% juice to obtain a mixture that is 50% juice.

\n" ); document.write( "Consider the three percentages 22, 50, and 100 on a number line. The difference between 22 and 50 is 28; the difference between 50 and 100 is 50. That means the two ingredients must be mixed in the ratio 28:50; since 50% is closer to 22% than it is to 100%, the larger portion must be the original liter (1000 ml) of 22% juice.

\n" ); document.write( "The problem is then solved using a proportion:

\n" ); document.write( "50:28 = 1000:x
\n" ); document.write( "1000:560 = 1000:x

\n" ); document.write( "ANSWER: 560 ml

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