document.write( "Question 117145: \r
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document.write( "y2+11y=28 \n" );
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Algebra.Com's Answer #85319 by checkley71(8403) ![]() You can put this solution on YOUR website! Y^2+11Y=28 \n" ); document.write( "Y^2+11Y-28=0 \n" ); document.write( "USING THE QUADRATIC EQUATION: \n" ); document.write( "WE GET \n" ); document.write( "Y=(-11+-SQRT[11^2-4*1*-28])/2*1 \n" ); document.write( "Y=(-11+-SQRT[121+112])/2 \n" ); document.write( "Y=(-11+-SQRT[233)/2 \n" ); document.write( "Y=(-11+-15.26)/2 \n" ); document.write( "Y=(-11+15.26)/2 \n" ); document.write( "Y=4.26/2 \n" ); document.write( "Y=2.13 ANSWER. \n" ); document.write( "Y=(-11-15.26)/2 \n" ); document.write( "Y=-26.26/2 \n" ); document.write( "Y=-13.13 ANSWER. \n" ); document.write( " \n" ); document.write( " |