document.write( "Question 429498: two runners start at a certain point simultaneously, going the the same directions, the speed fo one runner is two thirds of the speed of the other runner. if at the end of 3 hours they are 6 miles apart, what is the speed of each runner? \n" ); document.write( "
Algebra.Com's Answer #853185 by ikleyn(53427)\"\" \"About 
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\n" ); document.write( "Two runners start at a certain point simultaneously, going the same directions, the speed for one runner is two thirds
\n" ); document.write( "of the speed of the other runner. If at the end of 3 hours they are 6 miles apart, what is the speed of each runner?
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\n" ); document.write( "\n" ); document.write( "        The solution of the other tutor is incorrect.\r
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document.write( "Let x be \"One\" runner speed, in mph.\r\n" );
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document.write( "Then the \"other\" runner speed is  \"%283%2F2%29x\" mph  <<<---===  it is the true meaning of the problem's condition.\r\n" );
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document.write( "The \"distance \" equation is\r\n" );
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document.write( "    \"3%2A%28%283%2F2%29x%29\" - \"3x\" = 6  miles  (the difference of the ran distances in 3 hours)\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    \"%289%2F2%29x\" - 3x = 6,\r\n" );
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document.write( "    9x - 6x = 12,\r\n" );
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document.write( "       3x   = 12,\r\n" );
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document.write( "        x   = 12/3 = 4.\r\n" );
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document.write( "Answer.  The slower runner' speed is 4 mph.  The faster runner' speed is  \"%283%2F2%29%2A4\" = 3*2 = 6 mph.\r\n" );
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