document.write( "Question 1210514: For a positive integer n, let \tau(n) be the sum of the positive integer divisors of n. Find the number of values of n, where 1 \le n \le 25, such that \tau(n) = 1. \n" ); document.write( "
Algebra.Com's Answer #853182 by greenestamps(13248) You can put this solution on YOUR website! \n" ); document.write( "The problem as posted is either (1) trivial or (2) posted incorrectly. \n" ); document.write( "The described function is the sum of the positive integer divisors of the positive integer n. \n" ); document.write( "For every positive integer n greater than 1, the divisors include both 1 and n, so the sum of the integer divisors of n is at least 1+n. \n" ); document.write( "So (trivially) 1 is the only positive integer n for which the sum of the divisors of n is equal to 1; therefor, the number of positive integers that satisfy the given condition is 1. \n" ); document.write( "ANSWER: 1 \n" ); document.write( " \n" ); document.write( " |