document.write( "Question 1164820: ln{[(𝑥^15)(x-1)^1/2]/(3x-16)}=𝐴ln𝑥+𝐵ln(𝑥−1)+𝐶ln(3𝑥−16)\r
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Algebra.Com's Answer #853176 by MathTherapy(10810)\"\" \"About 
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document.write( "ln{[(𝑥^15)(x-1)^1/2]/(3x-16)}=𝐴ln𝑥+𝐵ln(𝑥−1)+𝐶ln(3𝑥−16)\r\n" );
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document.write( "1)with the constant A=?\r\n" );
document.write( "2)the constant B=?\r\n" );
document.write( "3)and the constant C=?\r\n" );
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document.write( " = Aln(x) + Bln(x - 1) + Cln(3x - 16)\r\n" );
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document.write( " = Aln(x) + Bln(x - 1) + Cln(3x - 16)\r\n" );
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document.write( "\"15ln%28x%29+%2B+%281%2F2%29ln%28x+-+1%29+-+ln%283x+-+16%29\" = Aln(x) + Bln(x - 1) + Cln(3x - 16)\r\n" );
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document.write( " 15ln(x) + \"highlight_green%281%2F2%29\"ln(x - 1) - 1ln(3x - 16)\r\n" );
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document.write( "  Aln(x) +  Bln(x - 1) + Cln(3x - 16)\r\n" );
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document.write( "Comparing coefficients above, we see that
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