document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117263>Question 117263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "A Chemist ahs 25% and a 50% acid soultion. How much of each soultion should be used to form 200 ml of a 35% acid soultion. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85315 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .25X+.50(200-X)=200*.35<BR>\n" );
document.write( ".25X+100-.50X=70<BR>\n" );
document.write( "-.25X=70-100<BR>\n" );
document.write( "-.25X=-30<BR>\n" );
document.write( "X=-30/-.25<BR>\n" );
document.write( "X=120 ML OF 25% ACID IS REQUIRED.<BR>\n" );
document.write( "200-120=80 ML OF 50% ACID IS ALSO REQUIRED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".25*120+.50*80=70<BR>\n" );
document.write( "30+40=70<BR>\n" );
document.write( "70=70 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );