document.write( "Question 1210504: If A and B are positive 2 digest integers, how many solutions are there of the equation 2a+3b=100 \n" ); document.write( "
Algebra.Com's Answer #853063 by math_tutor2020(3827)\"\" \"About 
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\n" ); document.write( "Answer: 9\r
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\n" ); document.write( "\n" ); document.write( "Reasoning\r
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\n" ); document.write( "\n" ); document.write( "It sounds like \"digest\" should be \"digit\".\r
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\n" ); document.write( "\n" ); document.write( "I'm assuming the question is:
\n" ); document.write( "\"If A and B are positive two-digit integers, how many solutions are there to the equation 2a+3b = 100?\"\r
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\n" ); document.write( "\n" ); document.write( "Let's look at the related equation 2a+3b = 1, since we can multiply both sides by 100 later.\r
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\n" ); document.write( "\n" ); document.write( "Through fairly quick trial-and-error, you should find an integer solution is (a,b) = (-1,1)
\n" ); document.write( "Another method is to look at the graph of 2x+3y = 1 to find a lattice point, or you can use the Extended Euclidean Algorithm.\r
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\n" ); document.write( "\n" ); document.write( "Since (-1,1) is a solution we can state that
\n" ); document.write( "2a+3b = 1
\n" ); document.write( "2*(-1)+3*(1) = 1\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 100 to get,
\n" ); document.write( "2*(-1)+3*(1) = 1
\n" ); document.write( "100*( 2*(-1)+3*(1) ) = 100*1
\n" ); document.write( "100*2*(-1) + 100*3*(1) = 100
\n" ); document.write( "2*( 100*(-1) ) + 3*(100*1) = 100
\n" ); document.write( "2*( -100 ) + 3*(100) = 100
\n" ); document.write( "This demonstrates that (a,b) = (-100,100) is an integer solution to 2a+3b = 100.
\n" ); document.write( "Unfortunately a = -100 is not positive, and it's not a two-digit number either.
\n" ); document.write( "A similar problem shows up with b as well.
\n" ); document.write( "We must require that 10 <= a <= 99 and 10 <= b <= 99.
\n" ); document.write( "The symbol <= means \"less than or equal to\".\r
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\n" ); document.write( "\n" ); document.write( "2x+3y = 100 solves to y = (-2/3)x+(100/3)
\n" ); document.write( "The slope -2/3 will tell us how to go from one integer point to another on this line.
\n" ); document.write( "Start at (-100,100).
\n" ); document.write( "Move down 2, right 3 to arrive at (-97,98)
\n" ); document.write( "Move down 2, right 3 to arrive at (-94,96)
\n" ); document.write( "etc\r
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\n" ); document.write( "\n" ); document.write( "This \"down 2, right 3\" pattern can be expressed like this
\n" ); document.write( "a = -100+3t
\n" ); document.write( "b = 100-2t
\n" ); document.write( "where t is an integer.
\n" ); document.write( "If t = 0, then it leads to (a,b) = (-100,100)
\n" ); document.write( "If t = 1, then it leads to (a,b) = (-97,98)
\n" ); document.write( "If t = 2, then it leads to (a,b) = (-94,96)
\n" ); document.write( "and so on.
\n" ); document.write( "If t was negative, then you go the opposite direction \"up 2, left 3\".\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "10 <= a <= 99
\n" ); document.write( "10 <= -100+3t <= 99
\n" ); document.write( "10+100 <= -100+3t+100 <= 99+100
\n" ); document.write( "110 <= 3t <= 199
\n" ); document.write( "110/3 <= 3t/3 <= 199/3
\n" ); document.write( "36.67 <= t <= 66.33 approximately
\n" ); document.write( "Since t is an integer we round the lower bound up to the nearest integer; while the upper bound gets pulled down to the nearest integer.
\n" ); document.write( "Note how t = 36 is too small since it leads to a = 8; while t = 67 is too large because it leads to a = 101.\r
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\n" ); document.write( "\n" ); document.write( "Anyways, we go from
\n" ); document.write( "36.67 <= t <= 66.33
\n" ); document.write( "to
\n" ); document.write( "37 <= t <= 66\r
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\n" ); document.write( "\n" ); document.write( "Meanwhile,
\n" ); document.write( "10 <= b <= 99
\n" ); document.write( "10 <= 100-2t <= 99
\n" ); document.write( "10-100 <= 100-2t-100 <= 99-100
\n" ); document.write( "-90 <= -2t <= -1
\n" ); document.write( "-90/(-2) >= -2t/(-2) >= -1/(-2) .... inequality signs flip
\n" ); document.write( "45 >= t >= 0.5
\n" ); document.write( "0.5 <= t <= 45
\n" ); document.write( "1 <= t <= 45 .... rounding to nearest integer
\n" ); document.write( "The inequality signs flipped because we divided all sides by a negative number.\r
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\n" ); document.write( "\n" ); document.write( "Overlap these two intervals
\n" ); document.write( "37 <= t <= 66
\n" ); document.write( "1 <= t <= 45
\n" ); document.write( "To get the interval 37 <= t <= 45
\n" ); document.write( "I recommend drawing out a number line.\r
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\n" ); document.write( "\n" ); document.write( "This set of t values will make both 10 <= a <= 99 and 10 <= b <= 99 true simultaneously where a = -100+3t and b = 100-2t.\r
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\n" ); document.write( "\n" ); document.write( "How many integers are in the set {37,38,...,45}?
\n" ); document.write( "We want the 37 to go to 1, the 38 to go to 2, etc.
\n" ); document.write( "Subtract 36 from each item and you'll get the set {1,2,...,9}\r
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\n" ); document.write( "\n" ); document.write( "Or you could say 45-37+1 = 9
\n" ); document.write( "The formula I used is that there are n-m+1 items in the set {m,m+1,m+2,...,n-1,n} where m,n are integers and m < n.
\n" ); document.write( "Note the -37+1 portion combines to -36, which is what we subtracted from each item of the previous set.\r
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\n" ); document.write( "\n" ); document.write( "We determined there are 9 integer solutions to the equation 2a+3b = 100 where a,b are positive two-digit integers.
\n" ); document.write( "Using a spreadsheet, or something like Python, the set of all solutions we're after is this
\n" ); document.write( "a = 11, b = 26
\n" ); document.write( "a = 14, b = 24
\n" ); document.write( "a = 17, b = 22
\n" ); document.write( "a = 20, b = 20
\n" ); document.write( "a = 23, b = 18
\n" ); document.write( "a = 26, b = 16
\n" ); document.write( "a = 29, b = 14
\n" ); document.write( "a = 32, b = 12
\n" ); document.write( "a = 35, b = 10
\n" ); document.write( "Each time 'a' goes up by 3, b drops by 2.
\n" ); document.write( "It seems like your teacher only cares about the number of solutions, rather than the solutions themselves. So this portion is likely optional.
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