document.write( "Question 730245: In a lake, there is a patch of lily pads. Every day the patch doubles in size. If it takes 48 days for the patch to cover the entire lake, how long would it take for the patch to cover half of the lake? \n" ); document.write( "
Algebra.Com's Answer #853059 by MathTherapy(10587)\"\" \"About 
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document.write( "In a lake, there is a patch of lily pads. Every day the patch doubles in size. If it takes 48 days for the patch to cover\r\n" );
document.write( "the entire lake, how long would it take for the patch to cover half of the lake? \r\n" );
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document.write( "I wholeheartedly agree with Tutor @Ikleyn that the patch will take 47 days to cover \"1%2F2\" of the lake, considering\r\n" );
document.write( "that its growth DOUBLES every day.\r\n" );
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document.write( "For this exponential growth scenario, we need to use the Simple Discrete Growth Formula: \"f%28t%29+=+a%28b%29%5Et\", or \"f%28x%29+=+a%28b%29%5Ex\", where: \r\n" );
document.write( "                                f(x) = Growth percent/fraction at a particular time (max being 100, or 1, or \"f%28x%29+%3C=+1\")\r\n" );
document.write( "                                   x = time period during growth\r\n" );
document.write( "                                   a = Initial/Beginning growth percent/fraction (\"a+%3C=+1\")\r\n" );
document.write( "                                   b = growth rate <=== this can also be represented by 1 + r \r\n" );
document.write( " \"f%28x%29+=+a%28b%29%5Ex\" \r\n" );
document.write( "\"f%2848%29+=+a%282%29%5E48\" ---- Substituting 48 for x, and 2 for b\r\n" );
document.write( "   \"1+=+a%282%29%5E48\" ---- Substituting 1 (100%) for f(48)\r\n" );
document.write( "Initial percent/fraction of lake covered, or a = \"1%2F2%5E48\"\r\n" );
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document.write( "       \"f%28x%29+=+a%28b%29%5Ex\" \r\n" );
document.write( "       \"f%28x%29+=+%281%2F2%5E48%29%282%29%5Ex\" ----- Substituting \"1%2F2%5E48\" for a, and 2 for b\r\n" );
document.write( "         \"1%2F2+=+%281%2F2%5E48%29%282%29%5Ex\" ----- Substituting \"1%2F2\" for f(x)\r\n" );
document.write( "     \"2%5E%28-+1%29+=+%282%5E%28-+48%29%29%282%5Ex%29\" -- Converting \"1%2F2\" to \"2%5E%28-+1%29\", and \"1%2F2%5E48\" to \"2%5E%28-+48%29\"\r\n" );
document.write( "     \"2%5E%28-+1%29+=+2%5E%28%28-+48+%2B+x%29%29\"\r\n" );
document.write( "       - 1 = - 48 + x ----- BASES are equal, and so are the exponents\r\n" );
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document.write( "Time it takes for the patch to cover \"1%2F2\" of the lake, or x = - 1 + 48 = 47 days.
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