document.write( "Question 1165619: A physician claims that joggers' maximal volume oxygen uptake is greater than the average of all adults. A sample of 15 joggers has a mean of 43.6 milliliters per kilogram (ml/kg) and a standard deviation of 6 ml/kg. If the average of all adults is 36.7 ml/kg, is there enough evidence to support the physician's claim at = 0.05?
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document.write( "First, identify the alternative and the null hypotheses.
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document.write( "Second, calculate the critical value and
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document.write( "Next, use the appropriate formula.
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document.write( "Finally, decide whether or not to reject the null hypothesis. \n" );
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Algebra.Com's Answer #853058 by amarjeeth123(573) ![]() You can put this solution on YOUR website! This is a one-way t-test \n" ); document.write( "test stat is a t(0.975, df=14)= (xbar-mean)/s/sqrt(n) \n" ); document.write( "Ho: means are the same or the joggers are less \n" ); document.write( "Ha: Joggers are more \n" ); document.write( "critical value t > 1.761 \n" ); document.write( "t=(43.6-36.7)/6/sqrt(15) \n" ); document.write( "=6.9*sqrt(15)/6=4.45 \n" ); document.write( "Reject Ho. Maximal oxygen uptake by joggers is more than the average of all adults. \n" ); document.write( "p-value=0.0003 \n" ); document.write( " |