document.write( "Question 253874: beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 240 g of beryllium-11 to decompose into 7.5g of beryllium-11? \r
\n" ); document.write( "\n" ); document.write( "based on the forumula provided in the text book C(t)=C(0)2e^-t/h\r
\n" ); document.write( "\n" ); document.write( "where C(0) = 240, C(t)=7.5 ,h=13.8\r
\n" ); document.write( "\n" ); document.write( "7.5/240=2e^-t/13.8\r
\n" ); document.write( "\n" ); document.write( "this was a s far as i got
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Algebra.Com's Answer #853054 by ikleyn(53339)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds.
\n" ); document.write( "How long will it take 240 g of beryllium-11 to decompose into 7.5 g of berlyium-11?
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\n" ); document.write( "\n" ); document.write( "This problem is very special and very specific.\r
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\n" ); document.write( "\n" ); document.write( "For the complete solution,  there is  NO  NEED  to write many-store complicated exponential functions.\r
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\n" ); document.write( "\n" ); document.write( "There is a special method and a special approach/reasoning,  and this problem
\n" ); document.write( "is  SPECIALLY  CREATED  for you to learn this special solution method from me.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the ratio   \"240%2F7.5\"   is   32.\r
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\n" ); document.write( "\n" ); document.write( "        It means that  5  (five) half-lives happened in this decay process\r
\n" ); document.write( "\n" ); document.write( "        from 240 gram of Beryllium-11 to 7.5 grams of Beryllium-11,  because   \"2%5E5\" = 32.\r
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\n" ); document.write( "\n" ); document.write( "5  half-lives is  5  times  13.8  seconds,  or  5 * 13.8 = 69 seconds.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER.   It will take  69 seconds for 240 grams of   Beryllium-11  to decompose into  7.5 grams of Beryllium-11.
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\n" ); document.write( "\n" ); document.write( "        Solved and explained in a way how it  SHOULD  be done \r
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