document.write( "Question 730115: Berlyium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 2400g of berlyium-11 to decompose into 75g of berlyium-11?\r
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\n" ); document.write( "\n" ); document.write( "Thats the question, and I tried solving it but im stuck. This is what I have so far:
\n" ); document.write( "75=2400 x 2^-t/13.8
\n" ); document.write( "0.01325=27.6 (-t)
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Algebra.Com's Answer #853053 by ikleyn(53570)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds.
\n" ); document.write( "How long will it take 2400g of beryllium-11 to decompose into 75g of berlyium-11?
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\n" ); document.write( "\n" ); document.write( "First, from chemical and physical points of views,  your post was written terrifically.
\n" ); document.write( "I mean the name of Beryllium.  So I re-wrote it in correct form.\r
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\n" ); document.write( "\n" ); document.write( "Next,  this problem is very special and very specific.\r
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\n" ); document.write( "\n" ); document.write( "For the complete solution,  there is  NO  NEED  to write many-store complicated exponential functions.\r
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\n" ); document.write( "\n" ); document.write( "There is a special method and a special approach/reasoning,  and this problem
\n" ); document.write( "is  SPECIALLY  CREATED  for you to learn this special solution method from me.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the ratio   \"2400%2F75\"   is   32.\r
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\n" ); document.write( "\n" ); document.write( "        It means that  5  (five) half-lives happened in this decay process\r
\n" ); document.write( "\n" ); document.write( "        from 2400 gram of Beryllium-11 to 75 grams of Beryllium-11,  because   \"2%5E5\" = 32.\r
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\n" ); document.write( "\n" ); document.write( "5  half-lives is  5  times  13.8  seconds,  or  5 * 13.8 = 69 seconds.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER.   It will take  69 seconds for 2400 grams of   Beryllium-11  to decompose to  75 grams of Beryllium-11.
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\n" ); document.write( "\n" ); document.write( "        Solved and explained in a way how it  SHOULD  be done \r
\n" ); document.write( "\n" ); document.write( "                    and how it is  EXPECTED  to be done.\r
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