document.write( "Question 117272: fraction problem\r
\n" ); document.write( "\n" ); document.write( " numerator sqrt5-2x
\n" ); document.write( "denominator 3 =1
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Algebra.Com's Answer #85305 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
From your explanation, I think this is what you mean,
\n" ); document.write( "\"sqrt%285-2x%29%2F3=1\"
\n" ); document.write( "\"sqrt%285-2x%29=3\" Multiply both sides by (3).
\n" ); document.write( "\"%285-2x%29=9\" Square both sides.
\n" ); document.write( "\"-2x=4\" Subtract (5) from boths sides.
\n" ); document.write( "\"highlight%28x=-2%29\" Divide both sides by (-2).
\n" ); document.write( "Always check your answer.
\n" ); document.write( "\"sqrt%285-2x%29%2F3=1\"
\n" ); document.write( "\"sqrt%285-2%28-2%29%29%2F3=1\"
\n" ); document.write( "\"sqrt%285%2B4%29%2F3=1\"
\n" ); document.write( "\"sqrt%289%29%2F3=1\"
\n" ); document.write( "\"3%2F3=1\"
\n" ); document.write( "\"1=1\"
\n" ); document.write( "True statement.
\n" ); document.write( "Good answer.
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