document.write( "Question 730282: Solve the following equation for x:(1/8)^x=25\r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #853049 by ikleyn(53339)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Solve the following equation for x: (1/8)^x=25
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Your starting equation is\r\n" );
document.write( "\r\n" );
document.write( "    \"%281%2F8%29%5Ex\" = 25.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is the same as\r\n" );
document.write( "\r\n" );
document.write( "    \"2%5E%28-3x%29\" = 25.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Multiply both sides by 4.  You will get an equivalent equation\r\n" );
document.write( "\r\n" );
document.write( "    \"2%5E%282-3x%29\" = 100.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Take logarithm base 2 of both sides\r\n" );
document.write( "\r\n" );
document.write( "    2 - 3x = \"log%282%2C%28100%29%29\",\r\n" );
document.write( "\r\n" );
document.write( "    2 - 3x = \"2%2Alog%282%2C%2810%29%29\",\r\n" );
document.write( "\r\n" );
document.write( "    \"2+-+2%2Alog%282%2C%2810%29%29\" = 3x,\r\n" );
document.write( "\r\n" );
document.write( "    x = \"%282+-+2%2Alog%282%2C%2810%29%29%29%2F3\" = -1.547952063...\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  x = -1.547952, approximately.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "CHECK.  \"%281%2F8%29%5E%28-1.547952063%29\" = 24.9999999866,  which is good match.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );