document.write( "Question 1210497: In trapezoid $EFGH,$ $\overline{EF} \parallel \overline{GH},$ and $P$ is the point on $\overline{EH}$ such that $EP:PH = 1:1$. If the area of triangle $PEG$ is $4$, and the area of triangle $EFG$ is $4$, then find the area of trapezoid $EFGH$. \n" ); document.write( "

Algebra.Com's Answer #852999 by ikleyn(53299) $\"\"$ $\"About$

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\n" ); document.write( "In trapezoid EFGH, EF parallel GH, and P is the point on EH such that EP:PH = 1:1.
\n" ); document.write( "If the area of triangle PEG is 4, and the area of triangle EFG is 4, then find the area of trapezoid EFGH.
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\n" ); document.write( "\n" ); document.write( " This problem is easy.\r
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document.write( "The area of trapezoid EFGH is the sum of areas of three triangles\r\n" );
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document.write( "     =  +  + .\r\n" );
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document.write( " = 4  is given;\r\n" );
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document.write( " = 4  is given;\r\n" );
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document.write( " =  = 4,  because triangles PGH and PGE have equal bases EP = PH\r\n" );
document.write( "                                                                           and common altitude to their bases.\r\n" );
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document.write( "Therefore,  = 4 + 4 + 4 = 12 square units.    ANSWER\r\n" );
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