document.write( "Question 1210498: Quadrilateral $ABCD$ is a parallelogram. Let $E$ be a point on $\overline{AB},$ and let $F$ be the intersection of lines $DE$ and $BC.$ The area of triangle $EBC$ is $4,$ and the area of triangle $ABC$ is $4.$ Find the area of parallelogram $ABCD$. \n" ); document.write( "
Algebra.Com's Answer #852998 by ikleyn(53299)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Quadrilateral ABCD is a parallelogram. Let E be a point on AB, and let F be the intersection of lines
\n" ); document.write( "DE and BC. The area of triangle EBC is 4, and the area of triangle ABC is 4.
\n" ); document.write( "Find the area of parallelogram ABCD.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The post is SELF-CONTRADICTORY and describes a situation which NEVER may happen.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Indeed, triangle ABC has the base AB and the height 'h', which is the height of the parallelogram
\n" ); document.write( "drawn to base AB.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Triangle EBC has the base EB and the same height 'h', but EB is part of BC, shorter than BC itself.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "But under this condition, the areas of triangles ABC and EBC can not be equal.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This is a contradiction, which kills the problem to the death and ruins it into dust.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );