document.write( "Question 731820: 7 teams are in the Christmas Basketball Tournament. Each team will play each other only once.
\n" ); document.write( "~ graph a network of the tournament
\n" ); document.write( "~ how many games were played in total?
\n" ); document.write( "~ if 2 more teams were added to the tournament list, how many games would then be played?
\n" ); document.write( "~ show your work and explain your answer \n" ); document.write( "

Algebra.Com's Answer #852969 by ikleyn(53595) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "7 teams are in the Christmas Basketball Tournament. Each team will play each other only once.
\n" ); document.write( "~ graph a network of the tournament
\n" ); document.write( "~ how many games were played in total?
\n" ); document.write( "~ if 2 more teams were added to the tournament list, how many games would then be played?
\n" ); document.write( "~ show your work and explain your answer
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document.write( "Each of 7 teams plays with each of 6 teams.\r\n" );
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document.write( "So, our first wish is to multiply 7 by 6 and to get 42.\r\n" );
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document.write( "But then a brilliant thought comes to our mind: it tells that doing this way,\r\n" );
document.write( "we count each play twice. \r\n" );
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document.write( "Therefore, we divide 42 by 2 and get the correct  ANSWER   = .\r\n" );
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document.write( "If 2 more teams were added, when we calculate similarly: we multiply 7+2 = 9 by 9-1=8\r\n" );
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document.write( "    9*8 = 72,\r\n" );
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document.write( "and then divide by 2 to get the  ANSWER  .\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved (without making a graph of network, which is the job bordering with madness).\r
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