document.write( "Question 1165713: a) The probability of being a smoker among a group of cases with lung cancer is 0.75. Calculate the probability that in a group of 6 cases, you have atleast 3 smokers.
\n" ); document.write( "b) What are the expected value and variance of the number of smokers?
\n" ); document.write( "c) The number of babies born in a day at a hospital's maternity wing follows a Poisson distribution with a mean of 4 in a day. Calculate the probability that five babies are born during a particular day in this maternity wing.
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Algebra.Com's Answer #852961 by ikleyn(53339)\"\" \"About 
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\n" ); document.write( "a) The probability of being a smoker among a group of cases with lung cancer is 0.75.
\n" ); document.write( " Calculate the probability that in a group of 6 cases, you have at least 3 smokers.\r
\n" ); document.write( "\n" ); document.write( "b) What are the expected value and variance of the number of smokers?\r
\n" ); document.write( "\n" ); document.write( "c) The number of babies born in a day at a hospital's maternity wing follows a Poisson distribution
\n" ); document.write( " with a mean of 4 in a day. Calculate the probability that five babies are born during a particular day
\n" ); document.write( " in this maternity wing.
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\n" ); document.write( "\n" ); document.write( "        In the post by  @CPhill,  his calculations in part  (a)  are  INCORRECT.\r
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document.write( "For example, he calculates in part (a)\r\n" );
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document.write( "    P(X=3) = binom{6}{3}*(0.75)^3*(0.25)^{3} = 20 \times 0.421875 \times 0.015625 \approx 0.032959\r\n" );
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document.write( "which is wrong.\r\n" );
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document.write( "The correct calculation in this case is\r\n" );
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document.write( "    P(X=3) = C(6,3)*0.75^3*0.25^3 = 20*0.75^3*0.25^3 = 0.131835938,\r\n" );
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document.write( "and then his wrong contribution of P(X=3) goes into his final answer to part (a).\r\n" );
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