document.write( "Question 732140: Divide 56 Into Two Parts Such That Three Times The First Parts Exceeds One Third Of The Second By 48. The Parts Are \n" ); document.write( "

Algebra.Com's Answer #852918 by ikleyn(53479) $\"\"$ $\"About$

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\n" ); document.write( "Divide 56 Into Two Parts Such That Three Times The First Parts Exceeds One Third Of The Second By 48.
\n" ); document.write( "The Parts Are
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document.write( "Let x be first part; then the second part is (56-x).\r\n" );
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document.write( "The imposed condition is\r\n" );
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document.write( "    3x -  = 48.\r\n" );
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document.write( "To solve this equation, multiply all the terms by 3\r\n" );
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document.write( "    9x - (56-x) = 48*3,\r\n" );
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document.write( "    9x + x = 144 + 56,\r\n" );
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document.write( "      10x  =    200,\r\n" );
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document.write( "        x  =    200/10 = 20.\r\n" );
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document.write( "ANSWER.  The parts are 20 and 56-20 = 36.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The answer in the post by @lynnlo is incorrect.\r
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\n" ); document.write( "\n" ); document.write( "Simply ignore his post.\r
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