document.write( "Question 1166031: A sales clerk in the departmental store claims that 65% of the shoppers entering the store leave without making a purchase. A random sample of 60 shoppers showed that 40 of them left without buying anything. Are these sample results consistent with the claim of the sales clerk at 1% level of significance? \n" ); document.write( "
Algebra.Com's Answer #852871 by CPhill(2189) You can put this solution on YOUR website! This problem requires a **one-sample proportion Z-test** to determine if the sample results are consistent with the sales clerk's claim. \r \n" ); document.write( "\n" ); document.write( "## 📝 Hypothesis Test for Population Proportion\r \n" ); document.write( "\n" ); document.write( "### 1. Define Hypotheses\r \n" ); document.write( "\n" ); document.write( "The sales clerk claims that 65% of shoppers leave without purchasing, so the null hypothesis ($H_0$) is that the true population proportion ($p$) is $0.65$. The alternative hypothesis ($H_1$) tests if the sample is *inconsistent* with this claim, suggesting the proportion is different.\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis ($H_0$):** $p = 0.65$ (The true proportion of shoppers leaving without a purchase is 65%). \n" ); document.write( "* **Alternative Hypothesis ($H_1$):** $p \neq 0.65$ (The true proportion is different from 65%).\r \n" ); document.write( "\n" ); document.write( "This is a **two-tailed test**.\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### 2. Determine the Level of Significance and Critical Values\r \n" ); document.write( "\n" ); document.write( "* **Level of Significance ($\alpha$):** $1\%$ or $0.01$. \n" ); document.write( "* Since this is a two-tailed test, the significance is split between the two tails ($\alpha/2 = 0.01/2 = 0.005$). \n" ); document.write( "* The **critical Z-values** corresponding to an area of $0.005$ in each tail are found from the standard normal distribution table: \n" ); document.write( " $$Z_{\text{critical}} = \mathbf{\pm 2.58}$$\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### 3. Calculate Test Statistic\r \n" ); document.write( "\n" ); document.write( "We use the sample data to calculate the test statistic ($Z_{\text{calc}}$).\r \n" ); document.write( "\n" ); document.write( "#### A. Sample Proportion ($\hat{p}$) \n" ); document.write( "* Sample size ($n$) = 60 \n" ); document.write( "* Number of shoppers leaving without purchase ($x$) = 40 \n" ); document.write( "* Sample proportion ($\hat{p}$) is the observed proportion: \n" ); document.write( " $$\hat{p} = \frac{x}{n} = \frac{40}{60} \approx \mathbf{0.6667}$$\r \n" ); document.write( "\n" ); document.write( "#### B. Standard Error ($SE$) \n" ); document.write( "We use the claimed population proportion ($p_0 = 0.65$) to calculate the standard error for the test statistic: \n" ); document.write( "$$SE = \sqrt{\frac{p_0 (1 - p_0)}{n}} = \sqrt{\frac{0.65 (1 - 0.65)}{60}}$$ \n" ); document.write( "$$SE = \sqrt{\frac{0.65 \times 0.35}{60}} = \sqrt{\frac{0.2275}{60}} \approx \sqrt{0.003792} \approx \mathbf{0.06158}$$\r \n" ); document.write( "\n" ); document.write( "#### C. Calculated Z-Score ($Z_{\text{calc}}$) \n" ); document.write( "$$Z_{\text{calc}} = \frac{\hat{p} - p_0}{SE} = \frac{0.6667 - 0.65}{0.06158}$$ \n" ); document.write( "$$Z_{\text{calc}} = \frac{0.0167}{0.06158} \approx \mathbf{0.27}$$\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### 4. Decision and Conclusion\r \n" ); document.write( "\n" ); document.write( "* **Decision Rule:** Reject $H_0$ if $|Z_{\text{calc}}| > |Z_{\text{critical}}|$. \n" ); document.write( "* **Comparison:** \n" ); document.write( " $$|0.27| \text{ is not greater than } |2.58|$$ \n" ); document.write( " $0.27 < 2.58$\r \n" ); document.write( "\n" ); document.write( "The calculated test statistic ($Z_{\text{calc}} = 0.27$) falls within the non-rejection region (the area between -2.58 and 2.58).\r \n" ); document.write( "\n" ); document.write( "**Conclusion:**\r \n" ); document.write( "\n" ); document.write( "Since the test statistic is not in the critical region, we **fail to reject the null hypothesis ($H_0$)**.\r \n" ); document.write( "\n" ); document.write( "The sample results ($\hat{p} \approx 66.67\%$) are **consistent with the claim** of the sales clerk ($p = 65\%$) at the $1\%$ level of significance. The small difference observed is attributed to **random sampling variation**. \n" ); document.write( " |