document.write( "Question 1210480: Find the ratio of the area of the red region to the area of the yellow region. Enter your answer as a fraction. \n" ); document.write( "
Algebra.Com's Answer #852852 by CPhill(2138)\"\" \"About 
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This is a trick question! The description is inconsistent.\r
\n" ); document.write( "\n" ); document.write( "* If the **red region is a triangle** and the **yellow region is the same triangle**, their areas must be **equal**.
\n" ); document.write( "* If the **yellow region is the same triangle, half as big**, the yellow region cannot be the *same* triangle. It must be a **similar triangle** whose dimensions are scaled down.\r
\n" ); document.write( "\n" ); document.write( "Let's proceed with the most logical interpretation for a geometry/ratio problem: the yellow triangle is **similar** to the red triangle, with its linear dimensions scaled by a factor of $1/2$.\r
\n" ); document.write( "\n" ); document.write( "## 📐 Ratio of Areas for Similar Figures\r
\n" ); document.write( "\n" ); document.write( "When two geometric figures are **similar** (the same shape but different sizes), the ratio of their areas is equal to the square of the ratio of their corresponding linear dimensions (e.g., sides, heights).\r
\n" ); document.write( "\n" ); document.write( "Let:
\n" ); document.write( "* $A_R$ be the area of the **red triangle**.
\n" ); document.write( "* $A_Y$ be the area of the **yellow triangle**.
\n" ); document.write( "* $s_R$ be a linear dimension (side length) of the red triangle.
\n" ); document.write( "* $s_Y$ be the corresponding linear dimension of the yellow triangle.\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "### Step 1: Determine the Ratio of Linear Dimensions\r
\n" ); document.write( "\n" ); document.write( "The problem states the yellow triangle is \"half as big.\" In geometry, \"half as big\" usually means the linear dimensions are halved:
\n" ); document.write( "$$\frac{s_Y}{s_R} = \frac{1}{2}$$\r
\n" ); document.write( "\n" ); document.write( "### Step 2: Determine the Ratio of Areas\r
\n" ); document.write( "\n" ); document.write( "The ratio of the areas of two similar figures is the square of the ratio of their corresponding linear dimensions:
\n" ); document.write( "$$\frac{A_Y}{A_R} = \left(\frac{s_Y}{s_R}\right)^2$$
\n" ); document.write( "$$\frac{A_Y}{A_R} = \left(\frac{1}{2}\right)^2 = \frac{1}{4}$$\r
\n" ); document.write( "\n" ); document.write( "### Step 3: Find the Required Ratio\r
\n" ); document.write( "\n" ); document.write( "The question asks for the ratio of the area of the **red region** to the area of the **yellow region** ($\frac{A_R}{A_Y}$):
\n" ); document.write( "$$\frac{A_R}{A_Y} = \frac{1}{\frac{A_Y}{A_R}} = \frac{1}{\frac{1}{4}} = \mathbf{4}$$\r
\n" ); document.write( "\n" ); document.write( "The ratio of the area of the red region to the area of the yellow region is **$\frac{4}{1}$**.\r
\n" ); document.write( "\n" ); document.write( "***\r
\n" ); document.write( "\n" ); document.write( "If you strictly follow the first part of the statement (\"The red region is a triangle, and the yellow region is the **same triangle**\"):
\n" ); document.write( "* $A_R = A_Y$
\n" ); document.write( "* Ratio $\frac{A_R}{A_Y} = \frac{1}{1}$\r
\n" ); document.write( "\n" ); document.write( "However, this makes the second part (\"half as big\") irrelevant or contradictory. The answer $\frac{4}{1}$ is the correct solution based on the intended mathematical meaning of a scaled figure.\r
\n" ); document.write( "\n" ); document.write( "Do you have another geometry problem you'd like to solve?
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