document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17680>Question 17680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 42.  One number plus two times the other number is 57.  What are the numbers?  The answers are 15 and 27 but I don't understand how to get there.  Could you help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8528 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 42.  One number plus two times the other number is 57.  What are the numbers?  The answers are 15 and 27 but I don't understand \r<BR>\n" );
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document.write( "let one number be =x<BR>\n" );
document.write( "let the other number be =y<BR>\n" );
document.write( "their sum =x+y=42..........(1)<BR>\n" );
document.write( "two times the other number =2y<BR>\n" );
document.write( "plus the first number x = x+2y=57...........(2)<BR>\n" );
document.write( "(2)-(1) ....x+2y-x-y=57-42=15<BR>\n" );
document.write( "y=15...substituting in (1),we get ..x+15=42<BR>\n" );
document.write( "x=42-15=27 </SPAN>\n" );
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