document.write( "Question 734376: if a takes an old sweeper 30 hour to clean a street and takes a new and old sweepers together only 7.5 hours to clean the same street, then how long would it take for new sweeper to cleanse the same street? \n" ); document.write( "
Algebra.Com's Answer #852717 by ikleyn(53431)\"\" \"About 
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\n" ); document.write( "if \"highlight%28cross%28a%29%29\" it takes an old sweeper 30 hour to clean a street and takes a new and old sweepers together
\n" ); document.write( "only 7.5 hours to clean the same street, then how long would it take for new sweeper
\n" ); document.write( "to \"highlight%28cross%28cleanse%29%29\" clean the same street?
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document.write( "From the problem, the combined rate of the old and the new sweepers is  \"1%2F7.5\"  of the job\r\n" );
document.write( "per hour, when they work together,\r\n" );
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document.write( "while the rate of the old sweeper is  \"1%2F30\"  of the job per hour.\r\n" );
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document.write( "So, the rate of the new sweeper, when it works alone, is the difference\r\n" );
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document.write( "    \"1%2F7.5\" - \"1%2F30\" = \"%2830-7.5%29%2F%287.5%2A30%29\" = \"21.5%2F%287.5%2A30%29\" = \"3%2F30\" = \"1%2F10\"\r\n" );
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document.write( "of the job per hour.\r\n" );
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document.write( "Hence, it will take 10 hours for the new sweeper to clean the street working alone.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "This method analyzing rate of work via fractions is very powerful and effective way solving such problems.\r
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