document.write( "Question 737462: The width of a rectangle is 18 feet less than the perimeter. the area of the rectangle is 2,040 square feet. What are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #852675 by ikleyn(53339) $\"\"$ $\"About$

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\n" ); document.write( "The width of a rectangle is 18 feet less than the perimeter. the area of the rectangle is 2,040 square feet.
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document.write( "W = (2W + 2L) - 18\r\n" );
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document.write( "Hence  W = 18 - 2L.\r\n" );
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document.write( "Write an equation for the area of the rectangle\r\n" );
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document.write( "    LW = 2040  square feet\r\n" );
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document.write( "    L*(18-2L) = 2040\r\n" );
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document.write( "    18L - 2L^2 = 2040\r\n" );
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document.write( "    2L^2 - 18L + 2040 = 0\r\n" );
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document.write( "    L^2 - 9L + 1020 = 0\r\n" );
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document.write( "Look at the discriminant\r\n" );
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document.write( "    d = b^2 - 4ac = (-9)^2 - 4*1*1020 = 81 - 4080 is negative number.\r\n" );
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document.write( "It tells that this quadratic equation has no real solutions.\r\n" );
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document.write( "Hence, the problem is defective and describes a situation which never may happen in real world.\r\n" );
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