document.write( "Question 740076: the perimiter of a rectangle is 96 inches the length is 3 more then twice the width. find the dimension \n" ); document.write( "

Algebra.Com's Answer #852673 by ikleyn(53354) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "the $\"highlight%28cross%28perimiter%29%29\"$ perimeter of a rectangle is 96 inches the length is 3 more $\"highlight%28cross%28then%29%29\"$ than twice the width.
\n" ); document.write( "find the dimension
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "x = the width\r\n" );
document.write( "2x+3 = the length.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The perimeter equation\r\n" );
document.write( "\r\n" );
document.write( "    x + (2x+3) + x + (2x+3) = 96  inches\r\n" );
document.write( "\r\n" );
document.write( "    6x + 6 = 96\r\n" );
document.write( "\r\n" );
document.write( "    6x = 96 - 6\r\n" );
document.write( "\r\n" );
document.write( "    6x =   90\r\n" );
document.write( "\r\n" );
document.write( "     x =   90/6 = 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The width is 15 inches;  the length is  2*15+3 = 33 inches.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );