document.write( "Question 741742: A box contains 2 red and 3 green balls.one ball is drawn from the box and replaced before another is drawn.what is the propability that at least one is red? \n" ); document.write( "
Algebra.Com's Answer #852624 by ikleyn(53107)\"\" \"About 
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\n" ); document.write( "A box contains 2 red and 3 green balls. One ball is drawn from the box and replaced before another is drawn.
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document.write( "The probability that at least one ball of the two is red is the sum\r\n" );
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document.write( "    P(1st is red, 2nd is green) + P(1st is green, 2nd is red) + P(both are red).\r\n" );
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document.write( "So, calculating this three-terms sum is one approach to solve the problem.\r\n" );
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document.write( "But there is another approach, more effective and less computationally consuming.\r\n" );
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document.write( "It is to calculate the probability \"at least one ball is red\" as the complement to the probability \r\n" );
document.write( "\"both balls are green\".\r\n" );
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document.write( "So, let calculate the probability that \"both balls are green\".  It is\r\n" );
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document.write( "    P(both balls are green) = \"%283%2F5%29%2A%283%2F5%29\" = \"9%2F25\".\r\n" );
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document.write( "Hence, \r\n" );
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document.write( "    P(at least one ball is red) = 1 - P(both balls are green) = 1 - \"9%2F25\" = \"%2825-9%29%2F25\" = \"16%2F25\".\r\n" );
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document.write( "ANSWER.  The probability that at least one ball is red is  \"16%2F25\".\r\n" );
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