document.write( "Question 739994: a rectangle has length 2squarerootxcm and width squarerootxcm. the length of a diagonal of the rectangle is the squareroot of 45cm.
\n" ); document.write( "1 find the area of the rectangle
\n" ); document.write( "2 the area of the square is twice the area of the rectangle.
\n" ); document.write( "find the length of a side of a square. \n" ); document.write( "

Algebra.Com's Answer #852601 by ikleyn(53431) $\"\"$ $\"About$

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\n" ); document.write( "a rectangle has length 2squarerootxcm and width squarerootxcm. the length of a diagonal of the rectangle is the squareroot of 45cm.
\n" ); document.write( "1 find the area of the rectangle
\n" ); document.write( "2 the area of the square is twice the area of the rectangle.
\n" ); document.write( "find the length of a side of a square.
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document.write( "             P a r t   1.\r\n" );
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document.write( "The length is  .  The width is  .\r\n" );
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document.write( "The diagonal is   =  = .\r\n" );
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document.write( "From the problem, we have this equation\r\n" );
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document.write( "     = .\r\n" );
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document.write( "Square both sides\r\n" );
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document.write( "    5x = 45\r\n" );
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document.write( "and find  x = 45/5 = 9.\r\n" );
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document.write( "Then the area of this rectangle is  Length*Width =  = 2*9 = 18 cm^2.   ANSWER\r\n" );
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document.write( "Part 1 is complete.\r\n" );
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document.write( "             P a r t   2.\r\n" );
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document.write( "The area of the square is twice the area of the rectangle, i.e.  2*18 = 36 cm^2.\r\n" );
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document.write( "Hence, the side of the square is   = 6 cm.    ANSWER\r\n" );
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document.write( "Part 2 is complete.\r\n" );
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