document.write( "Question 1210452: The number of treats Addie the cat eats per minute is normaly distributed with a mean of 400 treats and a standard deviation of 120 treats. Determine the following: If 21 minutes are selected at random, what is the probability that the mean number of treats consumed exceeded 440 treats? \n" ); document.write( "
Algebra.Com's Answer #852593 by Edwin McCravy(20081)\"\" \"About 
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document.write( "The number of treats Addie the cat beats per minute is normally distributed with\r\n" );
document.write( "a mean of 400 treats and a standard deviation of 120 treats. Determine the\r\n" );
document.write( "following: If 21 minutes are selected at random, what is the probability that\r\n" );
document.write( "the mean number of treats consumed exceeded 440 treats?\r\n" );
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document.write( "Calculate the standard error of the mean First, we need to find the standard\r\n" );
document.write( "error of the mean, which is the standard deviation of the sampling distribution.\r\n" );
document.write( "The formula is \r\n" );
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document.write( "\"sigma%5Bxbar%5D\"\"%22%22=%22%22\"\"sigma%2Fsqrt%28n%29\" where \"sigma\" is the population standard deviation and \"n\" is the sample size.\r\n" );
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document.write( "\"sigma%5Bxbar%5D\"\"%22%22=%22%22\"\"120%2Fsqrt%2821%29\"\"%22%22=%22%22\"\"26.186\"  approximately.\r\n" );
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document.write( "Calculate the Z-score\r\n" );
document.write( "\"Z\"\"%22%22=%22%22\"\"%28xbar-mu%29%2Fsigma%5Bxbar%5D%29\",\r\n" );
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document.write( "where xbar is the sample mean, \"mu\" is the population mean, and \"sigma%5Bxbar%5D\" is the standard error.  \r\n" );
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document.write( "\"Z\"\"%22%22=%22%22\"\"%28440-400%29%2F26.186=40%2F26.186=1.527\", approximately\r\n" );
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document.write( "We find the probability that the mean number of treats exceeded 440, which\r\n" );
document.write( "corresponds to the area to the right of the calculated z-score. Using a \r\n" );
document.write( "standard normal distribution table or calculator, the probability of a \r\n" );
document.write( "z-score being less than 1.527 is approximately 0.9366. Therefore, the\r\n" );
document.write( "probability of it being greater than 1.527 is:\r\n" );
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document.write( "\"P%28Z%3E1.527%29\"\"%22%22=%22%22\"\"1-P%28Z%3C1.527%29\"\"%22%22=%22%22\"\"1-0.9366=0.0634\"\r\n" );
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document.write( "Answer: 0.0634\r\n" );
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document.write( "Edwin
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