document.write( "Question 670863: I am not sure how to figure out a coin problem without how much it's worth for example: A bank contains 44 coins (nickles, dimes, quarters). There are twice as many dimes as nickles and 8 fewer nickles than quarters. How much money is in the bank? \n" ); document.write( "

Algebra.Com's Answer #852517 by n2(19) $\"\"$ $\"About$

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\n" ); document.write( "A bank contains 44 coins (nickels, dimes, quarters). There are twice as many dimes as nickels
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document.write( "Let x be the number of nickels.\r\n" );
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document.write( "Then the number of dimes is 2x, according to the problem,\r\n" );
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document.write( "and the number of quarters is (x+8).\r\n" );
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document.write( "Having this, write equation for the total number of coins\r\n" );
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document.write( "    x + 2x + (x+8) = 44.    (here 44 is the given total number of coins).\r\n" );
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document.write( "Simplify this equation and find x\r\n" );
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document.write( "    4x + 8 = 44,\r\n" );
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document.write( "    4x = 44 - 8 = 36,\r\n" );
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document.write( "     x =36/4 = 9.\r\n" );
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document.write( "So, there are 9 nickels in the bank,  2*9 = 18 dimes and 9+8 = 17 quarters.\r\n" );
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document.write( "Now you can easily find the value of the bank\r\n" );
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document.write( "    5*9 + 10*18 + 17*25 = 650 cents,  or 6.50 dollars.\r\n" );
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document.write( "ANSWER.  The value of the bank is $6.50.\r\n" );
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