document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674243>Question 674243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob spent 1/6 of his life as a child, 1/12 as an adolescent, and 1/7 as a bachelor, five years after he was married, he had a son who died 4 years before his father at half his father's final age. How long did bob live? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #852512 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13258)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=852512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Solving the problem using all of the given information is a good exercise.  However, logical reasoning gives the answer with very little work.<br><BR>\n" );
document.write( "In age problems, all numbers are whole numbers.  So in this problem, the age Bob lived to must be a multiple of 6, 12, and 7.<br><BR>\n" );
document.write( "The least common multiple of 6, 12, and 7 is 84; so the age Bob lived to is an integer multiple of 84.  Since twice 84 is an unreasonable answer for the age at which Bob died, the answer has to be 84.<br><BR>\n" );
document.write( "ANSWER: 84<br><BR>\n" );
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