document.write( "Question 117199: I forgot to bring my book home and only have the problem written down. \r
\n" ); document.write( "\n" ); document.write( "Maragaret and Sylvia leave the house at the same time traveling in opposite directions. Margaret travels 30mph faster than sylvia. After 2 hours they are 200 miles apart. How fast is each woman traveling?
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Algebra.Com's Answer #85248 by stanbon(75887)\"\" \"About 
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Margaret and Sylvia leave the house at the same time traveling in opposite directions. Margaret travels 30mph faster than sylvia. After 2 hours they are 200 miles apart. How fast is each woman traveling?
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\n" ); document.write( "Margaret DATA:
\n" ); document.write( "Distance = x miles ; Time = 2 hrs ; rate = d/t = x/2 mph
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\n" ); document.write( "Sylvia DATA:
\n" ); document.write( "Distance = 200-x miles ; Time = 2 hrs ; Rate = d/t = (200-x)/2\r
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Margaret rate = Sylvia rate +30
\n" ); document.write( "x/2 = (200-x)/2 + 30
\n" ); document.write( "x = 200-x + 60
\n" ); document.write( "2x = 260
\n" ); document.write( "x = 130 miles
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\n" ); document.write( "Margaret's rate = x/2 = 65 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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