document.write( "Question 619259: Find the center and radius of a sphere, x^2+y^2+z^2-4x+2y-6z+10=0 \n" ); document.write( "
Algebra.Com's Answer #852462 by ikleyn(53299)\"\" \"About 
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\n" ); document.write( "Find the center and radius of a sphere, x^2+y^2+z^2-4x+2y-6z+10=0
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\n" ); document.write( "\n" ); document.write( "        In the post by @Theo, the center is defined correctly,  while the radius is incorrect.\r
\n" ); document.write( "\n" ); document.write( "        I came to fix it.\r
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\n" ); document.write( "\n" ); document.write( "x^2+y^2+z^2-4x+2y-6z+10 = 0 becomes:
\n" ); document.write( "(x^2 - 4x) + (y^2 + 2y) + (z^2 - 6z) = -10 which becomes:
\n" ); document.write( "(x-2)^2 + (y+1)^2 + (z-3)^2 = -10 + 4 + 1 + 9 which becomes:
\n" ); document.write( "(x-2)^2 + (y+1)^2 + (z-3)^2 = 4.
\n" ); document.write( "center is (2,-1,3).
\n" ); document.write( "radius = sqrt(4) = 2.\r
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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