document.write( "Question 117199: I forgot to bring my book home and only have the problem written down. \r
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document.write( "Maragaret and Sylvia leave the house at the same time traveling in opposite directions. Margaret travels 30mph faster than sylvia. After 2 hours they are 200 miles apart. How fast is each woman traveling? \n" );
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Algebra.Com's Answer #85240 by checkley71(8403) ![]() You can put this solution on YOUR website! 2(30+X)+2X=200 \n" ); document.write( "60+2X+2X=200 \n" ); document.write( "4X=200-60 \n" ); document.write( "4X=140 \n" ); document.write( "X=140/4 \n" ); document.write( "X=35 MPH FOR SYLVIA. \n" ); document.write( "35+30=65 MPH FOR MARGARET. \n" ); document.write( "PROOF \n" ); document.write( "2*65+2*35=200 \n" ); document.write( "130+70=200 \n" ); document.write( "200=200 \n" ); document.write( " |