document.write( "Question 478361: ples please someone....I NEED HELP WITH THIS QUESTION I HAVE SUBMITTED IT SEVERAL TIMES THE FIRST TIME I DID NOT GIVE ALL OF THE INFORMATION, THE SECOND TIME I PUT IN THE WRONG EMAIL ADDRESS....I DESPERATELY NEED HELP WITH IT I DO NOT KNOW WHERE TO BEGIN AND CAN NOT FIND AN EXAMPLE THAT CAN GUIDE ME ALONG THE WAY SO THAT I WILL EVEN KNOW WHERE TO BEGIN....PLEASE HELP!!!! LET X BE A RANDOM VARIABLE WITH THE FOLLOWING PROBAILITY DISTRIBUTION\r
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\n" ); document.write( "\n" ); document.write( "DOES X HAVE A BINOMIAL DISTRIBUTION JUSTIFY YOUR ANSWER \n" ); document.write( "

Algebra.Com's Answer #852394 by ikleyn(52876) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "LET X BE A RANDOM VARIABLE WITH THE FOLLOWING PROBAILITY DISTRIBUTION
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document.write( "    X       0    1    2    3\r\n" );
document.write( "    P(X)  0.4  0.3  0.2  0.1\r\n" );
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DOES X HAVE A BINOMIAL DISTRIBUTION ? JUSTIFY YOUR ANSWER.
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\n" ); document.write( "\n" ); document.write( "        It is a good problem. It is good, because it is non-standard and is different from \r
\n" ); document.write( "\n" ); document.write( "        thousands other standard problems, that are usually offered in this area.\r
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\n" ); document.write( "\n" ); document.write( "        Standard problems check if you know what is written in textbooks.\r
\n" ); document.write( "\n" ); document.write( "        Non-standard problems check, in addition, if you able to think independently,\r
\n" ); document.write( "\n" ); document.write( "        and motivate you to be creative.\r
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\n" ); document.write( "\n" ); document.write( "        Tutor @Theo in his post wrote many words, but did not provide a direct solution.\r
\n" ); document.write( "\n" ); document.write( "        Meanwhile, the direct solution is simple, but requires to find and to apply some fresh idea.\r
\n" ); document.write( "\n" ); document.write( "        Therefore, it is educative and deserves your attention.\r
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document.write( "                - - - S O L U T I O N  - - - \r\n" );
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document.write( "Let's    for a minute that the distribution P(X) is a binomial.\r\n" );
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document.write( "Then the number of trials is 3, and should be some probability 'p' such that\r\n" );
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document.write( "    P(i) = ,  i = 0, 1, 2, 3.    (1)\r\n" );
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document.write( "According to (1), for i = 0 should be  P(0) = 0.4 =  =  = .\r\n" );
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document.write( "           It implies  p =  = 0.7368063  (rounded).\r\n" );
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document.write( "Next, according to (1), for i = 3 should be  \r\n" );
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document.write( "    P(3) = 0.1 =  =  = =  = 0.018231671.\r\n" );
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document.write( "Thus we got the   : we got the number of 0.018231671 for P(3), different from the given value P(3) = 0.1.\r\n" );
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document.write( "It    that the given distribution is   a binomial.\r\n" );
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\n" ); document.write( "\n" ); document.write( "At this point, the problem is solved completely.\r
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