document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117200>Question 117200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a cruise boat travels 24 miles downstream in 3 hours and returns to its starting point upstream in 6 hours. find the speed of the stream. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85239 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24/3=8 MPH FOR THE TRIP DOWNSTREAM.<BR>\n" );
document.write( "24/6=4 MPH FOR THE RETURN TRIP.<BR>\n" );
document.write( "NOW YOU HAVE 2 EQUATIONS.<BR>\n" );
document.write( "R+S=8 WHERE WHERE R=THE RATE OF THE CRUISE BOAT & S=THE STREAM SPEED.<BR>\n" );
document.write( "R-S=4 NOW ADD THESE TO FIND THE.<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "2R=12<BR>\n" );
document.write( "R=12/2<BR>\n" );
document.write( "R=6 MPH RATE OF THE CRUISE BOAT. <BR>\n" );
document.write( "THEREFORE <BR>\n" );
document.write( "6+S=8<BR>\n" );
document.write( "S=8-6<BR>\n" );
document.write( "S=2 MPH FOR THE SPEED OF THE STREAM.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );