document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1210401>Question 1210401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9p^2+6p-8\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #852234 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=852234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is one of many ways to factor a quadratic like this, where the leading coefficient is not 1.<br><BR>\n" );
document.write( "Step 1: find the product of the leading coefficient and the constant term<BR>\n" );
document.write( "9(-8) = -72<br><BR>\n" );
document.write( "Step 2: find two integers (obviously one positive and one negative) whose product is -72 (from step 1) and whose sum is 6 (the coefficient of the linear term)<BR>\n" );
document.write( "-72 = (12)(-6)<br><BR>\n" );
document.write( "Step 3: break the linear term into two terms using the numbers from step 2<BR>\n" );
document.write( "9p^2+12p-6p-8<br><BR>\n" );
document.write( "Factor the new expression by grouping<BR>\n" );
document.write( "(9p^2+12p)+(-6p-8)<BR>\n" );
document.write( "3p(3p+4)+(-2)(3p+4)<BR>\n" );
document.write( "(3p-2)(3p+4)<br><BR>\n" );
document.write( "ANSWER: 9p^2+6p-8 = (3p-2)(3p+4)<br><BR>\n" );
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