document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117151>Question 117151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> While cleaning out the closet, john found a box of coins.  The box contained nickels, dimes, and quarters.  He added up the change and found that there were 85 coins totaling $6.25 in the box.  If there were 3 times as many nickles as dimes, how many quarters were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85223 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SETTING UP A TABLE THIS PROBLEM CAN BE SOLVED BY THE FOLLOWING PROCEDURE.<BR>\n" );
document.write( "START BY ASSIGNING MULTIPLES OF 10 TO THE DIMES COLUMN ADDING 3 TIMES THE NUMBER OF NICKLES AND SUBTRATING THESE TOTALS FROM 85 & MULTIPLYING THIS COUNT BY .25 TO SEE IF THIS TOTAL=6.25:<BR>\n" );
document.write( "NUMBER OF COINS---------85----85<BR>\n" );
document.write( "NUMBER OF QUARTERS----45-----5<BR>\n" );
document.write( "NUMBER OF DIMES=X------10----20<BR>\n" );
document.write( "NUMBER OF NICKLES=3X--30----60<BR>\n" );
document.write( "TOTAL AMOUNT----------14.25--6.25<BR>\n" );
document.write( "THUS WE HAVE 85 COINS (5*.25+20*.10=60*.5=6.25)<BR>\n" );
document.write( "ANSWER: 5 QUARTERS, 20 DIMES & 60 NICKLES. </SPAN>\n" );
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