document.write( "Question 1210397: Andrew bought some apples and pears. The ratio of the number of apples bought to the number of pears bought was 7:4. He spent $61.20. He paid $22.80 more for the apples than the pears. Each apple was $0.30 more than each pears.
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Algebra.Com's Answer #852208 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Andrew bought some apples and pears. The ratio of the number of apples bought to the number of pears bought was 7:4.
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document.write( "Let A be the amount he spent for apples.\r\n" );
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document.write( "Let P be the amount he spent for pears.\r\n" );
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document.write( "From the problem, we have these two equations\r\n" );
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document.write( "    A + P = 61.20,    (1)\r\n" );
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document.write( "    A - P = 22.80.    (2)\r\n" );
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document.write( "To find P, subtract equation (2) from equation (1).  You will get\r\n" );
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document.write( "    2P = 61.20 - 22.80\r\n" );
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document.write( "    2P = 38.4,  P = 38.4/2 = 19.2.\r\n" );
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document.write( "Thus, Andrew spent $19.20 for pears.  It is the answer for question (a).\r\n" );
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document.write( "From this, we conclude that Andrew spent  $61.20 - $19.20 = $42.00 for apples.\r\n" );
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document.write( "                   Now we start solving (b).\r\n" );
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document.write( "Andrew has 7n apples and 4n pears.  The number 'n' is unknown, and we want to find it.\r\n" );
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document.write( "The price for one apple is   = .\r\n" );
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document.write( "The price for one pear is   = .\r\n" );
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document.write( "The difference equation for price is\r\n" );
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document.write( "     -  = 0.3  dollars.\r\n" );
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document.write( "Simplify and find 'n'\r\n" );
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document.write( "     = 0.3,\r\n" );
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document.write( "    n =  = 4.\r\n" );
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document.write( "So, Andrew bought  7n = 7*4 = 28 apples and 4n = 4*4 = 16 pears.\r\n" );
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document.write( "It is the answer to question (b).\r\n" );
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