document.write( "Question 1167598: Let
\n" ); document.write( "b0, b1, b2, be the sequence defined by the explicit formula
\n" ); document.write( "bn = C · 5^n + D(−4)^n for each integer n ≥ 0,
\n" ); document.write( "where C and D are real numbers.
\n" ); document.write( "(a)
\n" ); document.write( "Find C and D so that
\n" ); document.write( "b0 = 0
\n" ); document.write( " and
\n" ); document.write( "b1 = −9.\r
\n" ); document.write( "\n" ); document.write( "b) Find C and D so that
\n" ); document.write( "b0 = 4
\n" ); document.write( " and
\n" ); document.write( "b1 = 11.\r
\n" ); document.write( "\n" ); document.write( "c)What is
\n" ); document.write( "b2 in this case?
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Algebra.Com's Answer #852196 by Resolver123(6)\"\" \"About 
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(a) \"b%5Bn%5D+=+c%2A5%5En+%2B+d%2A%28-4%29%5En\" for \"n%3E=0\"
\n" ); document.write( "means that \"b%5B0%5D+=+c%2A5%5E0+%2B+d%2A%28-4%29%5E0=c%2Bd=0\", by hypothesis, after direct substitution.
\n" ); document.write( "Also, inserting \"n=1\" into the formula gives \"b%5B1%5D+=+c%2A5%5E1+%2B+d%2A%28-4%29%5E1=-9\".
\n" ); document.write( "Hence, \"5c-4d=-9\".\r
\n" ); document.write( "\n" ); document.write( "From c + d = 0, we get d = -c.
\n" ); document.write( "Substituting this into the equation 5c - 4d = -9 gives 5c - 4(-c) = 5c+4c = -9,
\n" ); document.write( "or 9c = -9, or c = -1.
\n" ); document.write( "Therefore, c = -1, and d = -(-1) = 1.\r
\n" ); document.write( "\n" ); document.write( "(b) Similarly, \"b%5Bn%5D+=+c%2A5%5En+%2B+d%2A%28-4%29%5En\" gives \"b%5B0%5D+=+c%2A5%5E0+%2B+d%2A%28-4%29%5E0=c%2Bd=4\", or c + d = 4, or d = 4 - c. Also, \"b%5B1%5D+=+c%2A5%5E1+%2B+d%2A%28-4%29%5E1=11\", or 5c - 4d = 11.\r
\n" ); document.write( "\n" ); document.write( "Substituting, 5c - 4(4 - c) = 11, or 5c - 16 + 4c = 11.
\n" ); document.write( "This gives 9c = 27, or c = 3, which consequently gives d = 4 - 3 = 1.\r
\n" ); document.write( "\n" ); document.write( "(c) From part (b), we get \"b%5Bn%5D+=+3%2A5%5En+%2B+%28-4%29%5En\", so that \"b%5B2%5D+=+3%2A5%5E2+%2B+%28-4%29%5E2=3%2A25%2B16+=+75%2B16=91\"
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