document.write( "Question 1210389: The function f(x) = (1\x) is decreasing on its domain ( true or false)\r
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Algebra.Com's Answer #852170 by ikleyn(52754)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " First of all, I read this function as f(x) = 1/x, \r \n" ); document.write( "\n" ); document.write( " following to the standard rules commonly accepted in Math.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The domain is the set of all real numbers except of 0 (zero).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Function f(x) = 1/x has two branches: one over the set of positive 'x', \n" ); document.write( "another over the set of negative 'x'.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For each branch separately, function f(x) = 1/x is monotonic in each sub-domain.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or, more accurately, function f(x) = 1/x is monotonically decreases locally in each sib-domain.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To prove it, take the derivative: it is - \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The denominator \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You also can convince yourself by making a plot of this function.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For it, go to website https:\\www.desmos.com/calculator/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Print the formula for the function y = 1/x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You will get the plot instantly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The plot clearly shows that the function monotonically decreases as 'x' increases in the domain.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, locally for each branch, the function f(x) = 1/x monotonically decreases. \n" ); document.write( "You have this answer proved formally and demonstrated / illustrated visually.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But we can not say that function f(x) = 1/x is globally decreasing: when 'x' moves \n" ); document.write( "from negative values to positive values, the function 1/x jumps from negative values to positive, \n" ); document.write( "breaking monotonicity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, locally this function is monotonically decreasing, but globally it is not monotonic.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "//////////////////////////////////////\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " This problem is an elementary \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As I explained in my post above, locally and piece-wisely, the function is monotonically decreasing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But globally, it is NOT monotonic.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is OBVIOUS: compare these values of the function\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " x -2 -1 1 2 \r\n" ); document.write( "\r\n" ); document.write( " 1/x -0.5 -1 1 0.5\r\n" ); document.write( "\r\n" ); document.write( " decrease decrease\r\n" ); document.write( " increase\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "They show non-monotonic behavior.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Tutor @math_tutor2000 fell into this trap.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |