document.write( "Question 1165476: The volume of a truncated prism with an equilateral triangle as its horizontal base is equal to 3600 cm3. The vertical edges at
\n" ); document.write( "each corner are 4, 6, and 8 cm. respectively. Find one side of the base.
\n" ); document.write( "a. 22.37 b. 25.43 c. 37.22 d. 17.89
\n" ); document.write( "

Algebra.Com's Answer #852160 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "The volume of a truncated prism with an equilateral triangle as its horizontal base is equal to 3600 cm3.
\n" ); document.write( "The vertical edges at each corner are 4, 6, and 8 cm. respectively. Find one side of the base.
\n" ); document.write( "a. 22.37 b. 25.43 c. 37.22 d. 17.89
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "First, let's look at the position of the point at the sloped section, \r\n" );
document.write( "which is exactly over the center of the regular triangle at the base.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Vertical coordinate of this point is the arithmetic mean of the numbers 4, 6 and 8\r\n" );
document.write( "\r\n" );
document.write( "    z = \"%284%2B6%2B8%29%2F3\" = 6 cm  over the base plane.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Now, let's accept without a proof, that the volume of the truncated prism is the same \r\n" );
document.write( "as the volume of the regular prism with the same base and the height of 6 sm.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "If the side of the base is 'a', then the area of the base is  \"a%5E2%2A%28sqrt%283%29%2F4%29\" cm^2,\r\n" );
document.write( "\r\n" );
document.write( "and the volume of the regular prism is  \"a%5E2%2A6%2A%28sqrt%283%29%2F4%29\" cm^3 = \"a%5E2%2A%283%2Asqrt%283%29%2F2%29\" cm^3.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It gives us an equation for 'a'\r\n" );
document.write( "\r\n" );
document.write( "    \"a%5E2%2A%283%2Asqrt%283%29%2F2%29\" = 3600.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "From this equation\r\n" );
document.write( "\r\n" );
document.write( "    \"a%5E2\" = \"%283600%2A2%29%2F%283%2Asqrt%283%29%29\" = \"2400%2Fsqrt%283%29\" = \"%282400%2Asqrt%283%29%29%2F3\" = \"800%2Asqrt%283%29\",\r\n" );
document.write( "\r\n" );
document.write( "    a = \"sqrt%28800%2Asqrt%283%29%29\" = 37.22 cm  (rounded).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The size of the base is about 37.22 cm ,  which is option (c)  in the answer list.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );