document.write( "Question 1210356: find the range of
\n" ); document.write( " f(sqrt(x)) = x + 1 \n" ); document.write( "

Algebra.Com's Answer #852038 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "Find the range of
\n" ); document.write( "f(sqrt(x)) = x + 1.
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document.write( "In order for ' f ' in the left side be a function of real argument,  must be defined.\r\n" );
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document.write( "It requires for ' x ' to be a non-negative real number  x >= 0.\r\n" );
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document.write( "So, the domain of the function in the left side is the set  { x >= 0 }.\r\n" );
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document.write( "Then the range is the set of all real numbers  { y >= 1 }.    <<<---=== ANSWER\r\n" );
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