document.write( "Question 117148: use the point-slope form of the linear equation to find an equation of the line the given point. Then write the equation in standard form.\r
\n" ); document.write( "\n" ); document.write( "Slope -5/8;through (2,5)
\n" ); document.write( "

Algebra.Com's Answer #85198 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-5%2F8\" which goes through the point (\"2\",\"5\"), you can simply use the point-slope formula to find the equation:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-5=%28-5%2F8%29%28x-2%29\" Plug in \"m=-5%2F8\", \"x%5B1%5D=2\", and \"y%5B1%5D=5\" (these values are given)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-5=%28-5%2F8%29x%2B%28-5%2F8%29%28-2%29\" Distribute \"-5%2F8\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-5=%28-5%2F8%29x%2B5%2F4\" Multiply \"-5%2F8\" and \"-2\" to get \"5%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2F8%29x%2B5%2F4%2B5\" Add 5 to both sides to isolate y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2F8%29x%2B25%2F4\" Combine like terms \"5%2F4\" and \"5\" to get \"25%2F4\" (note: if you need help with combining fractions, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-5%2F8\" which goes through the point (\"2\",\"5\") is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-5%2F8%29x%2B25%2F4\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-5%2F8\" and the y-intercept is \"b=25%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-5%2F8%29x%2B25%2F4\" and plot the point (\"2\",\"5\"), we get (note: if you need help with graphing, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-5%2F8%29x%2B25%2F4\" through the point (\"2\",\"5\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-5%2F8\" and goes through the point (\"2\",\"5\"), this verifies our answer.
\n" ); document.write( "
\n" );