document.write( "Question 1210338: Determine the perimeter and area:
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Algebra.Com's Answer #851929 by ikleyn(52781)\"\" \"About 
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document.write( "The perimeter is (5 + 5) + (6+6) + \"pi%2Ar\" = \"10+%2B+12+%2B+3.14159265%2A%288%2F2%29\" = 34.5663706 m.\r\n" );
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document.write( "The area is the sum of the areas of two right-angled triangles PLUS the area of the rectangle \r\n" );
document.write( "PLUS the area of the semi-circle of the radius 8/2 = 4 m\r\n" );
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document.write( "Right angled triangles are (3-4-5)-triangles. The area of each such triangle is (1/2)*3*4 = 3*2 = 6 m^2.\r\n" );
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document.write( "So, the area under the question is \r\n" );
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document.write( "    2*6 + 6*8 + \"%281%2F2%29%2Api%2Ar%5E2\" = \"12+%2B+48+%2B+%281%2F2%29%2A3.14159265%2A4%5E2\" = 85.1327412 m^2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "This problem is  EXTREMELY  simple.\r
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\n" ); document.write( "\n" ); document.write( "It is of the level  \" take what you see in the picture,
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\n" ); document.write( "\n" ); document.write( "Thinking is not required and is not assumed . . . \r
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