document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179791>Question 1179791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area (in square units) of the region under the curve of the function f(x) = 3x − 1 on the interval [a, 4], where a < 4, is 12 square units, identify all the possible values of a.\r<BR>\n" );
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document.write( "what values are correct?\r<BR>\n" );
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document.write( "a. -3<BR>\n" );
document.write( "b. 0<BR>\n" );
document.write( "c. -16/5<BR>\n" );
document.write( "d. 8/3<BR>\n" );
document.write( "e. -2<BR>\n" );
document.write( "f. 7/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #851905 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52796)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=851905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .If the area (in square units) of the region under the curve of the function f(x) = 3x − 1 <BR>\n" );
document.write( "on the interval [a, 4], where a < 4, is 12 square units, identify all the possible values of a. what values are correct?<BR>\n" );
document.write( "a. -3<BR>\n" );
document.write( "b. 0<BR>\n" );
document.write( "c. -16/5<BR>\n" );
document.write( "d. 8/3<BR>\n" );
document.write( "e. -2<BR>\n" );
document.write( "f. 7/2<BR>\n" );
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document.write( "In the post by @CPhill, his solution has fatal errors and leads to wrong answer.\r<BR>\n" );
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document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "In section (3) of his solution, he correctly derived an equation for 'a'  3a^2 - 2a - 16 = 0,\r\n" );
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document.write( "but in section (4), he incorrectly factored it as (3a+8)*(a-2) = 0,\r\n" );
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document.write( "obtaining wrong solutions a = -8/3 and  a = 2.\r\n" );
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document.write( "Actually, the correct factoring is (3a-8)*(a+2) = 0, giving  a = 8/3  or  a = -2.\r\n" );
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document.write( "Then the further analysis leads to the answer  (d):  a = 8/3.\r\n" );
document.write( "</PRE>\r<BR>\n" );
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document.write( " </SPAN>\n" );
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