document.write( "Question 1210329: Yaro drove from a town Gaja to Banga. After 2 hours in the journey, he observed that he had covered 80 km and realized that if he continued driving at same average speed, he would end up being late for 15 minutes. If he decided to increase the average speed by 10 km/h, he would arrive at Banga 36 minutes earlier. Find the distance between Gaja and Banga. \n" ); document.write( "
Algebra.Com's Answer #851902 by greenestamps(13195)\"\" \"About 
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\n" ); document.write( "Let x be the remaining distance after he has traveled 80 km.

\n" ); document.write( "Since he traveled 80 km in the first 2 hours, his speed was 40 km/hr. If he increases his speed by 10 km/hr, his new speed will be 50 km/hr.

\n" ); document.write( "If he continues at his current speed of 40 km/hr, he will be 15 minutes late; if he increases his speed to 50 km/hr, he will be 36 minutes early.

\n" ); document.write( "The difference in the amounts of time to travel the remaining distance x at speeds of 40 km/hr and 50 km/hr is 15+36 = 51 minutes = 17/20 hours:

\n" ); document.write( "\"x%2F40-x%2F50=17%2F20\"

\n" ); document.write( "Multiply by the least common denominator 200 to clear fractions:

\n" ); document.write( "\"5x-4x=170\"
\n" ); document.write( "\"x=170\"

\n" ); document.write( "The remaining distance is 170 km.

\n" ); document.write( "ANSWER: The distance between Gaja and Banga is 80+170 = 250 km

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